Which answer would score higher? Not sure where to start? Explain this Answer A Al3++2e−→Al\mathrm{Al^{3+} + 2e^- \rightarrow Al}Al3++2e−→Al at the cathode and O2−→O2+2e−\mathrm{O^{2-} \rightarrow O_2 + 2e^-}O2−→O2+2e− at the anode. Each ion changes into its element. Answer B Al3++3e−→Al\mathrm{Al^{3+} + 3e^- \rightarrow Al}Al3++3e−→Al at the cathode and 2O2−→O2+4e−\mathrm{2O^{2-} \rightarrow O_2 + 4e^-}2O2−→O2+4e− at the anode. Atoms and charge balance in both equations.