Which answer would score higher? Not sure where to start? Explain this Answer A 25.0÷100=0.2525.0 \div 100 = 0.2525.0÷100=0.25 mol CaCO₃. The 1:11:11:1 ratio gives 0.250.250.25 mol CO₂, so its mass is 0.25×44=11.00.25 \times 44 = 11.00.25×44=11.0 g. Answer B 25.0÷100=0.2525.0 \div 100 = 0.2525.0÷100=0.25 mol CaCO₃. The two products double this to 0.500.500.50 mol CO₂, so its mass is 0.50×44=22.00.50 \times 44 = 22.00.50×44=22.0 g.