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AQA · GCSE · Combined Science · Higher

Mass of the trolley calculation

Q02.5 3 marks

Use the Physics Equations Sheet to answer questions 02.4 and 02.5.

A resultant force of 0.42 N acts on a different trolley.

The acceleration of the trolley is 1.2 m/s².

Calculate the mass of the trolley.

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Marking points

  1. 1 Substitute the force and acceleration into F=maF=ma: 0.42=m×1.20.42=m\times1.2.
  2. 2 Rearrange to find mass: m=0.421.2m=\frac{0.42}{1.2}.
  3. 3 Calculate the mass as 0.35 kg0.35\ \mathrm{kg}.

Full-mark answer

F=maF=ma, so 0.42=m×1.20.42=m\times1.2. Therefore m=0.421.2=0.35 kgm=\frac{0.42}{1.2}=0.35\ \mathrm{kg}.

Why this answer loses marks

m=0.42×1.2=0.504 kgm=0.42\times1.2=0.504\ \mathrm{kg}

This multiplies force by acceleration instead of dividing force by acceleration.

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