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AQA · GCSE · Combined Science · Higher

Mass of ice produced calculation

Q02.2 3 marks

A scientist cooled the air inside a container.

Calculate the mass of ice produced.

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Marking points

  1. 1 Use consistent units and substitute energy and latent heat into E=mLE = mL, for example 0.70=m×3300.70 = m \times 330.
  2. 2 Rearrange to find the mass, for example m=0.70330m = \frac{0.70}{330}.
  3. 3 Calculate the mass as 0.0021 kg0.0021\ \mathrm{kg}.

Full-mark answer

E=mLE = mL, so 0.70=m×3300.70 = m \times 330. Therefore m=0.70330=0.0021 kgm = \frac{0.70}{330} = 0.0021\ \mathrm{kg}.

Why this answer loses marks

700330=2.1 kg\frac{700}{330}=2.1\ \mathrm{kg}

This converts the energy to joules but leaves the latent heat in kJ/kg, so the units are inconsistent.