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AQA · GCSE · Combined Science · Higher

Spring extension from elastic energy

Q05.4 3 marks

The spring can store a maximum of 1800 J of elastic potential energy before it becomes inelastically deformed.

Calculate the maximum extension of the spring before the spring becomes inelastically deformed.

spring constant = 225 N/m

Use the Physics Equations Sheet.

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Marking points

  1. 1 Use the elastic potential energy equation and substitute Ee=1800 JE_e=1800\ \text{J} and k=225 N/mk=225\ \text{N/m}.
  2. 2 Rearrange correctly for the extension, including the square root.
  3. 3 Give the maximum extension as 4 m4\ \text{m}.

Full-mark answer

Using Ee=12ke2E_e=\frac{1}{2}ke^2: 1800=12×225×e21800=\frac{1}{2}\times225\times e^2. Therefore e=2×1800225=4 me=\sqrt{\frac{2\times1800}{225}}=4\ \text{m}.

Why this answer loses marks

16 m16\ \text{m}

This is e2e^2, not ee; the square root has not been taken.