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AQA · GCSE · Combined Science · Higher

Mass of the trolley calculation

Q02.4 3 marks

When the resultant force on the trolley was 0.63 N the acceleration of the trolley was 2.1 m/s². Calculate the mass of the trolley.

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Marking points

  1. 1 Substitute the given values into F=maF=ma: 0.63=m×2.10.63=m\times2.1.
  2. 2 Rearrange to make mass the subject: m=0.632.1m=\frac{0.63}{2.1}.
  3. 3 Give the mass as 0.30 kg0.30\ \text{kg}, or 0.3 kg0.3\ \text{kg}.

Full-mark answer

F=maF=ma, so 0.63=m×2.10.63=m\times2.1. Therefore m=0.632.1=0.30 kgm=\frac{0.63}{2.1}=0.30\ \text{kg}.

Why this answer loses marks

0.63×2.1=1.323 kg0.63\times2.1=1.323\ \text{kg}

The equation must be rearranged so that mass is force divided by acceleration, not force multiplied by acceleration.

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