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Second iteration through puzzle positions
getTile(row, column) returns the tile value at a position on the 3 x 3 board; the blank space is represented by 0.
| int ref1, ref2; |
| for (int i = 0; i < 3; i++) |
| { |
| for (int j = 0; j < 3; j++) |
| { |
| if (getTile(i, j) == 0) |
| { |
| ref1 = i; |
| ref2 = j; |
| } |
| } |
| } |
Explain the purpose of the second iteration structure in the program in Figure 16.
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Marking points
- 1 Explains that the inner/second loop iterates through the board columns.
Full-mark answer
It iterates through the columns of each row.
Why this answer loses marks
It repeats the search inside the first loop.
This describes nesting but does not name the dimension traversed by the second loop.